(4n-2)=(3n+8)

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Solution for (4n-2)=(3n+8) equation: 



(4n-2)=(3n+8)

We move all terms to the left:

(4n-2)-((3n+8))=0

We get rid of parentheses

4n-((3n+8))-2=0



We calculate terms in parentheses: -((3n+8)), so:

(3n+8)

We get rid of parentheses

3n+8

Back to the equation:

-(3n+8)



We get rid of parentheses

4n-3n-8-2=0

We add all the numbers together, and all the variables

n-10=0

We move all terms containing n to the left, all other terms to the right

n=10

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