(4n-5)(4n-5)(2n)(2n)=14

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Solution for (4n-5)(4n-5)(2n)(2n)=14 equation:



(4n-5)(4n-5)(2n)(2n)=14
We move all terms to the left:
(4n-5)(4n-5)(2n)(2n)-(14)=0
We multiply parentheses ..
(+16n^2-20n-20n+25)2n2n-14=0
We multiply parentheses
32n^4-40n^3-40n^3+50n^2-14=0
We do not support enpression: n^4

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