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(4n-5)/7-(2n+1)/2=1/2-n
We move all terms to the left:
(4n-5)/7-(2n+1)/2-(1/2-n)=0
Domain of the equation: 2-n)!=0We add all the numbers together, and all the variables
We move all terms containing n to the left, all other terms to the right
-n)!=-2
n!=-2/1
n!=-2
n∈R
(4n-5)/7-(2n+1)/2-(-1n+1/2)=0
We get rid of parentheses
(4n-5)/7-(2n+1)/2+1n-1/2=0
We calculate fractions
There is no solution for this equation
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