(4p+9)(p+8)=0

Solution for (4p+9)(p+8)=0 equation:

(4p+9)(p+8)=0

We multiply parentheses ..

(+4p^2+32p+9p+72)=0

We get rid of parentheses

4p^2+32p+9p+72=0

We add all the numbers together, and all the variables

4p^2+41p+72=0

a = 4; b = 41; c = +72;
Δ = b2-4ac
Δ = 412-4·4·72
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(41)-23}{2*4}=\frac{-64}{8}
=-8
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(41)+23}{2*4}=\frac{-18}{8}
=-2+1/4
$