(4p-3)(p+12)=0

Solution for (4p-3)(p+12)=0 equation:

(4p-3)(p+12)=0

We multiply parentheses ..

(+4p^2+48p-3p-36)=0

We get rid of parentheses

4p^2+48p-3p-36=0

We add all the numbers together, and all the variables

4p^2+45p-36=0

a = 4; b = 45; c = -36;
Δ = b2-4ac
Δ = 452-4·4·(-36)
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2601}=51$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-51}{2*4}=\frac{-96}{8}
=-12
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+51}{2*4}=\frac{6}{8}
=3/4
$