(4p-7)(2p+3)=0

Solution for (4p-7)(2p+3)=0 equation:

(4p-7)(2p+3)=0

We multiply parentheses ..

(+8p^2+12p-14p-21)=0

We get rid of parentheses

8p^2+12p-14p-21=0

We add all the numbers together, and all the variables

8p^2-2p-21=0

a = 8; b = -2; c = -21;
Δ = b2-4ac
Δ = -22-4·8·(-21)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-26}{2*8}=\frac{-24}{16}
=-1+1/2
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+26}{2*8}=\frac{28}{16}
=1+3/4
$