(4r+16)/12=(5r-20)/5

Solution for (4r+16)/12=(5r-20)/5 equation:

(4r+16)/12=(5r-20)/5

We move all terms to the left:

(4r+16)/12-((5r-20)/5)=0

We calculate fractions


4r/()+(-((5r-20)*12)/()=0


We calculate terms in parentheses: +(-((5r-20)*12)/(), so:

-((5r-20)*12)/(

We multiply all the terms by the denominator


-((5r-20)*12)


We calculate terms in parentheses: -((5r-20)*12), so:

(5r-20)*12

We multiply parentheses

60r-240

Back to the equation:

-(60r-240)


We get rid of parentheses

-60r+240

Back to the equation:

+(-60r+240)


We get rid of parentheses

4r/()-60r+240=0

We multiply all the terms by the denominator


4r-60r*()+240*()=0

We add all the numbers together, and all the variables

4r-60r*()=0