(4t(2t+1))(4t(2t+1))=l

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Solution for (4t(2t+1))(4t(2t+1))=l equation: 


Simplifying
(4t(2t + 1))(4t(2t + 1)) = l

Reorder the terms:
(4t(1 + 2t))(4t(2t + 1)) = l
((1 * 4t + 2t * 4t))(4t(2t + 1)) = l
((4t + 8t2))(4t(2t + 1)) = l

Reorder the terms:
(4t + 8t2)(4t(1 + 2t)) = l
(4t + 8t2)((1 * 4t + 2t * 4t)) = l
(4t + 8t2)((4t + 8t2)) = l

Multiply (4t + 8t2) * (4t + 8t2)
(4t * (4t + 8t2) + 8t2 * (4t + 8t2)) = l
((4t * 4t + 8t2 * 4t) + 8t2 * (4t + 8t2)) = l
((16t2 + 32t3) + 8t2 * (4t + 8t2)) = l
(16t2 + 32t3 + (4t * 8t2 + 8t2 * 8t2)) = l
(16t2 + 32t3 + (32t3 + 64t4)) = l

Combine like terms: 32t3 + 32t3 = 64t3
(16t2 + 64t3 + 64t4) = l

Solving
16t2 + 64t3 + 64t4 = l

Solving for variable 't'.

Reorder the terms:
-1l + 16t2 + 64t3 + 64t4 = l + -1l

Combine like terms: l + -1l = 0
-1l + 16t2 + 64t3 + 64t4 = 0

The solution to this equation could not be determined.

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