(4t+1)/2=(t+5)/4+(t-3)/4

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Solution for (4t+1)/2=(t+5)/4+(t-3)/4 equation: 


t in (-oo:+oo)

(4*t+1)/2 = (t+5)/4+(t-3)/4 // - (t+5)/4+(t-3)/4

(4*t+1)/2-((t+5)/4)-((t-3)/4) = 0

(4*t+1)/2+(-1*(t+5))/4+(-1*(t-3))/4 = 0

(4*(4*t+1))/(2*4)+(-1*2*(t+5))/(2*4)+(-1*2*(t-3))/(2*4) = 0

4*(4*t+1)-1*2*(t+5)-1*2*(t-3) = 0

14*t-2*t-6+6 = 0

12*t = 0

(12*t)/(2*4) = 0

(12*t)/(2*4) = 0 // * 2*4

12*t = 0

12*t = 0 // : 12

t = 0

t = 0

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