(4t+1)/2=(t-5)/4+(t-3)/4

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Solution for (4t+1)/2=(t-5)/4+(t-3)/4 equation: 


t in (-oo:+oo)

(4*t+1)/2 = (t-5)/4+(t-3)/4 // - (t-5)/4+(t-3)/4

(4*t+1)/2-((t-5)/4)-((t-3)/4) = 0

(4*t+1)/2+(-1*(t-5))/4+(-1*(t-3))/4 = 0

(4*(4*t+1))/(2*4)+(-1*2*(t-5))/(2*4)+(-1*2*(t-3))/(2*4) = 0

4*(4*t+1)-1*2*(t-5)-1*2*(t-3) = 0

14*t-2*t+6+14 = 0

12*t+20 = 0

(12*t+20)/(2*4) = 0

(12*t+20)/(2*4) = 0 // * 2*4

12*t+20 = 0

12*t+20 = 0 // - 20

12*t = -20 // : 12

t = -20/12

t = -5/3

t = -5/3

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