(4t+1)/3=(t+5)/6+(t-3)/6

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Solution for (4t+1)/3=(t+5)/6+(t-3)/6 equation: 


t in (-oo:+oo)

(4*t+1)/3 = (t+5)/6+(t-3)/6 // - (t+5)/6+(t-3)/6

(4*t+1)/3-((t+5)/6)-((t-3)/6) = 0

(4*t+1)/3+(-1*(t+5))/6+(-1*(t-3))/6 = 0

(6*(4*t+1))/(3*6)+(-1*3*(t+5))/(3*6)+(-1*3*(t-3))/(3*6) = 0

6*(4*t+1)-1*3*(t+5)-1*3*(t-3) = 0

21*t-3*t-9+9 = 0

18*t = 0

(18*t)/(3*6) = 0

(18*t)/(3*6) = 0 // * 3*6

18*t = 0

18*t = 0 // : 18

t = 0

t = 0

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