(4t+3)=(2t-1)

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Solution for (4t+3)=(2t-1) equation: 



(4t+3)=(2t-1)

We move all terms to the left:

(4t+3)-((2t-1))=0

We get rid of parentheses

4t-((2t-1))+3=0



We calculate terms in parentheses: -((2t-1)), so:

(2t-1)

We get rid of parentheses

2t-1

Back to the equation:

-(2t-1)



We get rid of parentheses

4t-2t+1+3=0

We add all the numbers together, and all the variables

2t+4=0

We move all terms containing t to the left, all other terms to the right

2t=-4

t=-4/2

t=-2

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