(4t-3)/5=(t+3)/2

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Solution for (4t-3)/5=(t+3)/2 equation: 



(4t-3)/5=(t+3)/2

We move all terms to the left:

(4t-3)/5-((t+3)/2)=0

We calculate fractions


4t/()+(-((t+3)*5)/()=0



We calculate terms in parentheses: +(-((t+3)*5)/(), so:

-((t+3)*5)/(

We multiply all the terms by the denominator


-((t+3)*5)



We calculate terms in parentheses: -((t+3)*5), so:

(t+3)*5

We multiply parentheses

5t+15

Back to the equation:

-(5t+15)



We get rid of parentheses

-5t-15

Back to the equation:

+(-5t-15)



We get rid of parentheses

4t/()-5t-15=0

We multiply all the terms by the denominator


4t-5t*()-15*()=0

We add all the numbers together, and all the variables

4t-5t*()=0

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