(4t2-3)+(-2t2-2)=2t2-5

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Solution for (4t2-3)+(-2t2-2)=2t2-5 equation: 



(4t^2-3)+(-2t^2-2)=2t^2-5

We move all terms to the left:

(4t^2-3)+(-2t^2-2)-(2t^2-5)=0

We get rid of parentheses

-2t^2+4t^2-2t^2-2-3+5=0

We add all the numbers together, and all the variables

=0

t=0/1

t=0

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