(4u+1)(3+u)=0

Solution for (4u+1)(3+u)=0 equation:

Simplifying
(4u + 1)(3 + u) = 0

Reorder the terms:
(1 + 4u)(3 + u) = 0

Multiply (1 + 4u) * (3 + u)
(1(3 + u) + 4u * (3 + u)) = 0
((3 * 1 + u * 1) + 4u * (3 + u)) = 0
((3 + 1u) + 4u * (3 + u)) = 0
(3 + 1u + (3 * 4u + u * 4u)) = 0
(3 + 1u + (12u + 4u2)) = 0

Combine like terms: 1u + 12u = 13u
(3 + 13u + 4u2) = 0

Solving
3 + 13u + 4u2 = 0

Solving for variable 'u'.

Factor a trinomial.
(3 + u)(1 + 4u) = 0

Subproblem 1
Set the factor '(3 + u)' equal to zero and attempt to solve:

Simplifying
3 + u = 0

Solving
3 + u = 0

Move all terms containing u to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + u = 0 + -3

Combine like terms: 3 + -3 = 0
0 + u = 0 + -3
u = 0 + -3

Combine like terms: 0 + -3 = -3
u = -3

Simplifying
u = -3
Subproblem 2
Set the factor '(1 + 4u)' equal to zero and attempt to solve:

Simplifying
1 + 4u = 0

Solving
1 + 4u = 0

Move all terms containing u to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 4u = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 4u = 0 + -1
4u = 0 + -1

Combine like terms: 0 + -1 = -1
4u = -1

Divide each side by '4'.
u = -0.25

Simplifying
u = -0.25
Solution
u = {-3, -0.25}