(4u+6)(8+u)=0

Solution for (4u+6)(8+u)=0 equation:

(4u+6)(8+u)=0

We add all the numbers together, and all the variables

(4u+6)(u+8)=0

We multiply parentheses ..

(+4u^2+32u+6u+48)=0

We get rid of parentheses

4u^2+32u+6u+48=0

We add all the numbers together, and all the variables

4u^2+38u+48=0

a = 4; b = 38; c = +48;
Δ = b2-4ac
Δ = 382-4·4·48
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(38)-26}{2*4}=\frac{-64}{8}
=-8
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(38)+26}{2*4}=\frac{-12}{8}
=-1+1/2
$