(4u-12)-(1u+12)=18

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Solution for (4u-12)-(1u+12)=18 equation: 



(4u-12)-(1u+12)=18

We move all terms to the left:

(4u-12)-(1u+12)-(18)=0

We add all the numbers together, and all the variables

(4u-12)-(u+12)-18=0

We get rid of parentheses

4u-u-12-12-18=0

We add all the numbers together, and all the variables

3u-42=0

We move all terms containing u to the left, all other terms to the right

3u=42

u=42/3

u=14

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