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(4u-2)(6+u)=0
We add all the numbers together, and all the variables
(4u-2)(u+6)=0
We multiply parentheses ..
(+4u^2+24u-2u-12)=0
We get rid of parentheses
4u^2+24u-2u-12=0
We add all the numbers together, and all the variables
4u^2+22u-12=0
a = 4; b = 22; c = -12;
Δ = b2-4ac
Δ = 222-4·4·(-12)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-26}{2*4}=\frac{-48}{8} =-6 $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+26}{2*4}=\frac{4}{8} =1/2 $
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