(4u-7)/7=(u-4)/4

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Solution for (4u-7)/7=(u-4)/4 equation:



(4u-7)/7=(u-4)/4
We move all terms to the left:
(4u-7)/7-((u-4)/4)=0
We calculate fractions
4u/()+(-((u-4)*7)/()=0
We calculate terms in parentheses: +(-((u-4)*7)/(), so:
-((u-4)*7)/(
We multiply all the terms by the denominator
-((u-4)*7)
We calculate terms in parentheses: -((u-4)*7), so:
(u-4)*7
We multiply parentheses
7u-28
Back to the equation:
-(7u-28)
We get rid of parentheses
-7u+28
Back to the equation:
+(-7u+28)
We get rid of parentheses
4u/()-7u+28=0
We multiply all the terms by the denominator
4u-7u*()+28*()=0
We add all the numbers together, and all the variables
4u-7u*()=0

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