(4v+1)(4v-1)=

Solution for (4v+1)(4v-1)= equation:

Simplifying
(4v + 1)(4v + -1) = 0

Reorder the terms:
(1 + 4v)(4v + -1) = 0

Reorder the terms:
(1 + 4v)(-1 + 4v) = 0

Multiply (1 + 4v) * (-1 + 4v)
(1(-1 + 4v) + 4v * (-1 + 4v)) = 0
((-1 * 1 + 4v * 1) + 4v * (-1 + 4v)) = 0
((-1 + 4v) + 4v * (-1 + 4v)) = 0
(-1 + 4v + (-1 * 4v + 4v * 4v)) = 0
(-1 + 4v + (-4v + 16v2)) = 0

Combine like terms: 4v + -4v = 0
(-1 + 0 + 16v2) = 0
(-1 + 16v2) = 0

Solving
-1 + 16v2 = 0

Solving for variable 'v'.

Move all terms containing v to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + 16v2 = 0 + 1

Combine like terms: -1 + 1 = 0
0 + 16v2 = 0 + 1
16v2 = 0 + 1

Combine like terms: 0 + 1 = 1
16v2 = 1

Divide each side by '16'.
v2 = 0.0625

Simplifying
v2 = 0.0625

Take the square root of each side:
v = {-0.25, 0.25}