(4v+1)(v+3)=0

Solution for (4v+1)(v+3)=0 equation:

Simplifying
(4v + 1)(v + 3) = 0

Reorder the terms:
(1 + 4v)(v + 3) = 0

Reorder the terms:
(1 + 4v)(3 + v) = 0

Multiply (1 + 4v) * (3 + v)
(1(3 + v) + 4v * (3 + v)) = 0
((3 * 1 + v * 1) + 4v * (3 + v)) = 0
((3 + 1v) + 4v * (3 + v)) = 0
(3 + 1v + (3 * 4v + v * 4v)) = 0
(3 + 1v + (12v + 4v2)) = 0

Combine like terms: 1v + 12v = 13v
(3 + 13v + 4v2) = 0

Solving
3 + 13v + 4v2 = 0

Solving for variable 'v'.

Factor a trinomial.
(3 + v)(1 + 4v) = 0

Subproblem 1
Set the factor '(3 + v)' equal to zero and attempt to solve:

Simplifying
3 + v = 0

Solving
3 + v = 0

Move all terms containing v to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + v = 0 + -3

Combine like terms: 3 + -3 = 0
0 + v = 0 + -3
v = 0 + -3

Combine like terms: 0 + -3 = -3
v = -3

Simplifying
v = -3
Subproblem 2
Set the factor '(1 + 4v)' equal to zero and attempt to solve:

Simplifying
1 + 4v = 0

Solving
1 + 4v = 0

Move all terms containing v to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 4v = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 4v = 0 + -1
4v = 0 + -1

Combine like terms: 0 + -1 = -1
4v = -1

Divide each side by '4'.
v = -0.25

Simplifying
v = -0.25
Solution
v = {-3, -0.25}