(4v-4)/3=((v+1)/6)+2

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Solution for (4v-4)/3=((v+1)/6)+2 equation: 


v in (-oo:+oo)

(4*v-4)/3 = (v+1)/6+2 // - (v+1)/6+2

(4*v-4)/3-((v+1)/6)-2 = 0

(4*v-4)/3+(-1*(v+1))/6-2 = 0

(6*(4*v-4))/(3*6)+(-1*3*(v+1))/(3*6)+(-2*3*6)/(3*6) = 0

6*(4*v-4)-1*3*(v+1)-2*3*6 = 0

21*v-36-27 = 0

21*v-63 = 0

(21*v-63)/(3*6) = 0

(21*v-63)/(3*6) = 0 // * 3*6

21*v-63 = 0

21*v-63 = 0 // + 63

21*v = 63 // : 21

v = 63/21

v = 3

v = 3

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