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(4w+2)(5+w)=0
We add all the numbers together, and all the variables
(4w+2)(w+5)=0
We multiply parentheses ..
(+4w^2+20w+2w+10)=0
We get rid of parentheses
4w^2+20w+2w+10=0
We add all the numbers together, and all the variables
4w^2+22w+10=0
a = 4; b = 22; c = +10;
Δ = b2-4ac
Δ = 222-4·4·10
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-18}{2*4}=\frac{-40}{8} =-5 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+18}{2*4}=\frac{-4}{8} =-1/2 $
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