(4w+6)(4-w)=0

Solution for (4w+6)(4-w)=0 equation:

(4w+6)(4-w)=0

We add all the numbers together, and all the variables

(4w+6)(-1w+4)=0

We multiply parentheses ..

(-4w^2+16w-6w+24)=0

We get rid of parentheses

-4w^2+16w-6w+24=0

We add all the numbers together, and all the variables

-4w^2+10w+24=0

a = -4; b = 10; c = +24;
Δ = b2-4ac
Δ = 102-4·(-4)·24
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-22}{2*-4}=\frac{-32}{-8}
=+4
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+22}{2*-4}=\frac{12}{-8}
=-1+1/2
$