(4w+6)(5-w)=0

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Solution for (4w+6)(5-w)=0 equation:



(4w+6)(5-w)=0
We add all the numbers together, and all the variables
(4w+6)(-1w+5)=0
We multiply parentheses ..
(-4w^2+20w-6w+30)=0
We get rid of parentheses
-4w^2+20w-6w+30=0
We add all the numbers together, and all the variables
-4w^2+14w+30=0
a = -4; b = 14; c = +30;
Δ = b2-4ac
Δ = 142-4·(-4)·30
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-26}{2*-4}=\frac{-40}{-8} =+5 $
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+26}{2*-4}=\frac{12}{-8} =-1+1/2 $

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