(4w-2)(3-w)=0

Solution for (4w-2)(3-w)=0 equation:

(4w-2)(3-w)=0

We add all the numbers together, and all the variables

(4w-2)(-1w+3)=0

We multiply parentheses ..

(-4w^2+12w+2w-6)=0

We get rid of parentheses

-4w^2+12w+2w-6=0

We add all the numbers together, and all the variables

-4w^2+14w-6=0

a = -4; b = 14; c = -6;
Δ = b2-4ac
Δ = 142-4·(-4)·(-6)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-10}{2*-4}=\frac{-24}{-8}
=+3
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+10}{2*-4}=\frac{-4}{-8}
=1/2
$