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(4x)(5x+8)=0
We multiply parentheses
20x^2+32x=0
a = 20; b = 32; c = 0;
Δ = b2-4ac
Δ = 322-4·20·0
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-32}{2*20}=\frac{-64}{40} =-1+3/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+32}{2*20}=\frac{0}{40} =0 $
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