(4x)+(2x)+3(x-2)+(x+96)=360

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Solution for (4x)+(2x)+3(x-2)+(x+96)=360 equation: 



(4x)+(2x)+3(x-2)+(x+96)=360

We move all terms to the left:

(4x)+(2x)+3(x-2)+(x+96)-(360)=0

We add all the numbers together, and all the variables

6x+3(x-2)+(x+96)-360=0

We multiply parentheses

6x+3x+(x+96)-6-360=0

We get rid of parentheses

6x+3x+x+96-6-360=0

We add all the numbers together, and all the variables

10x-270=0

We move all terms containing x to the left, all other terms to the right

10x=270

x=270/10

x=27

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