(4x)+(3x+3)+(3x+3)=146

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Solution for (4x)+(3x+3)+(3x+3)=146 equation: 



(4x)+(3x+3)+(3x+3)=146

We move all terms to the left:

(4x)+(3x+3)+(3x+3)-(146)=0

We get rid of parentheses

4x+3x+3x+3+3-146=0

We add all the numbers together, and all the variables

10x-140=0

We move all terms containing x to the left, all other terms to the right

10x=140

x=140/10

x=14

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