(4x)+(7x-28)=65

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Solution for (4x)+(7x-28)=65 equation: 



(4x)+(7x-28)=65

We move all terms to the left:

(4x)+(7x-28)-(65)=0

We get rid of parentheses

4x+7x-28-65=0

We add all the numbers together, and all the variables

11x-93=0

We move all terms containing x to the left, all other terms to the right

11x=93

x=93/11

x=8+5/11

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