(4x)-2(x-3)+1=5-(x+3)

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Solution for (4x)-2(x-3)+1=5-(x+3) equation:



(4x)-2(x-3)+1=5-(x+3)
We move all terms to the left:
(4x)-2(x-3)+1-(5-(x+3))=0
We multiply parentheses
4x-2x-(5-(x+3))+6+1=0
We calculate terms in parentheses: -(5-(x+3)), so:
5-(x+3)
determiningTheFunctionDomain -(x+3)+5
We get rid of parentheses
-x-3+5
We add all the numbers together, and all the variables
-1x+2
Back to the equation:
-(-1x+2)
We add all the numbers together, and all the variables
2x-(-1x+2)+7=0
We get rid of parentheses
2x+1x-2+7=0
We add all the numbers together, and all the variables
3x+5=0
We move all terms containing x to the left, all other terms to the right
3x=-5
x=-5/3
x=-1+2/3

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