If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(4x)2=16x^2
We move all terms to the left:
(4x)2-(16x^2)=0
determiningTheFunctionDomain -16x^2+4x2=0
We add all the numbers together, and all the variables
-12x^2=0
a = -12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-12)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{-24}=0$
| -2n-2=2 | | -2n+2=2 | | 3(x-1)=2x11 | | -7+10x=73 | | x=0.4x+24 | | 5x/2-25=15 | | 12=x^2+2x-11 | | 11=x^2+2x-11 | | 16=k^2 | | 6y+3+y=17 | | 5=v+13/10 | | 49=d^2 | | 36=g^2 | | 25=c^2 | | 16=u^2 | | 5x+12=23 | | 14=-2(p-11) | | -5(z-3)+12=22 | | -59=-8s-19 | | 8z+19=43 | | 90=2y+8y | | -32=4(4+y) | | 1+s/6=1 | | 22+6y=70 | | 3=-u+10 | | -40+3x=48 | | 0.10d+0.25(d+6)=5.00. | | 8x^2-16x-15625=0 | | 12=4t+8 | | g-81/2=8 | | -3k+1=-11 | | 3q+9=15 |