(4x+-4)=(x+12)

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Solution for (4x+-4)=(x+12) equation: 



(4x+-4)=(x+12)

We move all terms to the left:

(4x+-4)-((x+12))=0

We add all the numbers together, and all the variables

(4x-4)-((x+12))=0

We get rid of parentheses

4x-((x+12))-4=0



We calculate terms in parentheses: -((x+12)), so:

(x+12)

We get rid of parentheses

x+12

Back to the equation:

-(x+12)



We get rid of parentheses

4x-x-12-4=0

We add all the numbers together, and all the variables

3x-16=0

We move all terms containing x to the left, all other terms to the right

3x=16

x=16/3

x=5+1/3

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