(4x+1)(4x-1)=0

Solution for (4x+1)(4x-1)=0 equation:

Simplifying
(4x + 1)(4x + -1) = 0

Reorder the terms:
(1 + 4x)(4x + -1) = 0

Reorder the terms:
(1 + 4x)(-1 + 4x) = 0

Multiply (1 + 4x) * (-1 + 4x)
(1(-1 + 4x) + 4x * (-1 + 4x)) = 0
((-1 * 1 + 4x * 1) + 4x * (-1 + 4x)) = 0
((-1 + 4x) + 4x * (-1 + 4x)) = 0
(-1 + 4x + (-1 * 4x + 4x * 4x)) = 0
(-1 + 4x + (-4x + 16x2)) = 0

Combine like terms: 4x + -4x = 0
(-1 + 0 + 16x2) = 0
(-1 + 16x2) = 0

Solving
-1 + 16x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + 16x2 = 0 + 1

Combine like terms: -1 + 1 = 0
0 + 16x2 = 0 + 1
16x2 = 0 + 1

Combine like terms: 0 + 1 = 1
16x2 = 1

Divide each side by '16'.
x2 = 0.0625

Simplifying
x2 = 0.0625

Take the square root of each side:
x = {-0.25, 0.25}