If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(4x+1)(5x+1)=0
We multiply parentheses ..
(+20x^2+4x+5x+1)=0
We get rid of parentheses
20x^2+4x+5x+1=0
We add all the numbers together, and all the variables
20x^2+9x+1=0
a = 20; b = 9; c = +1;
Δ = b2-4ac
Δ = 92-4·20·1
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-1}{2*20}=\frac{-10}{40} =-1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+1}{2*20}=\frac{-8}{40} =-1/5 $
| c+5=0.6 | | 4(7+x)=64 | | k-15.29=3.3 | | (x)(2x)(3+2x)=162 | | -4.35+x=-0.35 | | (11x-25)+24x+10)=90 | | 3x+5x+4=4x+4x+4 | | 6x+10=18x-34 | | 3x/6=-1 | | 7-7/2x=5 | | 4x+7+3x=12x+8 | | 2(4+6x)=4(3x+2) | | -8+2k-2+3k=k-3+5k-1 | | (4x-8)(x-12)=180 | | J=90+-5j | | 3.3=2n | | -4+3h=2h+10 | | 2727x=937x | | 2(y-1)=2y-2 | | -1=5+2h | | x/21=05 | | 3(2x+4)=2(2x+5)+2 | | 9a+9=a | | 6y-2=2(3y-1) | | -7+l-3+4l=5l-3+l-1 | | 2(y-1)=2y-1 | | 46=c/2+37 | | 3(2^(x-3))=108 | | 3(y-2)=-2(3y-4) | | 4b-46=42 | | 10x+5-3x=9+5x-2 | | 3(-2x+1)=-2(x-4) |