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(4x+1)(5x+1)=357
We move all terms to the left:
(4x+1)(5x+1)-(357)=0
We multiply parentheses ..
(+20x^2+4x+5x+1)-357=0
We get rid of parentheses
20x^2+4x+5x+1-357=0
We add all the numbers together, and all the variables
20x^2+9x-356=0
a = 20; b = 9; c = -356;
Δ = b2-4ac
Δ = 92-4·20·(-356)
Δ = 28561
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{28561}=169$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-169}{2*20}=\frac{-178}{40} =-4+9/20 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+169}{2*20}=\frac{160}{40} =4 $
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