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(4x+1)(5x-3)=79
We move all terms to the left:
(4x+1)(5x-3)-(79)=0
We multiply parentheses ..
(+20x^2-12x+5x-3)-79=0
We get rid of parentheses
20x^2-12x+5x-3-79=0
We add all the numbers together, and all the variables
20x^2-7x-82=0
a = 20; b = -7; c = -82;
Δ = b2-4ac
Δ = -72-4·20·(-82)
Δ = 6609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{6609}}{2*20}=\frac{7-\sqrt{6609}}{40} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{6609}}{2*20}=\frac{7+\sqrt{6609}}{40} $
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