(4x+1)(x+29)=

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Solution for (4x+1)(x+29)= equation:


Simplifying
(4x + 1)(x + 29) = 0

Reorder the terms:
(1 + 4x)(x + 29) = 0

Reorder the terms:
(1 + 4x)(29 + x) = 0

Multiply (1 + 4x) * (29 + x)
(1(29 + x) + 4x * (29 + x)) = 0
((29 * 1 + x * 1) + 4x * (29 + x)) = 0
((29 + 1x) + 4x * (29 + x)) = 0
(29 + 1x + (29 * 4x + x * 4x)) = 0
(29 + 1x + (116x + 4x2)) = 0

Combine like terms: 1x + 116x = 117x
(29 + 117x + 4x2) = 0

Solving
29 + 117x + 4x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(29 + x)(1 + 4x) = 0

Subproblem 1

Set the factor '(29 + x)' equal to zero and attempt to solve: Simplifying 29 + x = 0 Solving 29 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '-29' to each side of the equation. 29 + -29 + x = 0 + -29 Combine like terms: 29 + -29 = 0 0 + x = 0 + -29 x = 0 + -29 Combine like terms: 0 + -29 = -29 x = -29 Simplifying x = -29

Subproblem 2

Set the factor '(1 + 4x)' equal to zero and attempt to solve: Simplifying 1 + 4x = 0 Solving 1 + 4x = 0 Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + 4x = 0 + -1 Combine like terms: 1 + -1 = 0 0 + 4x = 0 + -1 4x = 0 + -1 Combine like terms: 0 + -1 = -1 4x = -1 Divide each side by '4'. x = -0.25 Simplifying x = -0.25

Solution

x = {-29, -0.25}

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