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(4x+1)+(5x)+(x+2)=113
We move all terms to the left:
(4x+1)+(5x)+(x+2)-(113)=0
We add all the numbers together, and all the variables
5x+(4x+1)+(x+2)-113=0
We get rid of parentheses
5x+4x+x+1+2-113=0
We add all the numbers together, and all the variables
10x-110=0
We move all terms containing x to the left, all other terms to the right
10x=110
x=110/10
x=11
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