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(4x+1)+(7x+3)+65=x
We move all terms to the left:
(4x+1)+(7x+3)+65-(x)=0
We add all the numbers together, and all the variables
-1x+(4x+1)+(7x+3)+65=0
We get rid of parentheses
-1x+4x+7x+1+3+65=0
We add all the numbers together, and all the variables
10x+69=0
We move all terms containing x to the left, all other terms to the right
10x=-69
x=-69/10
x=-6+9/10
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