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(4x+1)/(3)+3x-2=x+5
We move all terms to the left:
(4x+1)/(3)+3x-2-(x+5)=0
We add all the numbers together, and all the variables
3x+(4x+1)/3-(x+5)-2=0
We get rid of parentheses
3x+(4x+1)/3-x-5-2=0
We multiply all the terms by the denominator
3x*3+(4x+1)-x*3-5*3-2*3=0
We add all the numbers together, and all the variables
3x*3+(4x+1)-x*3-21=0
Wy multiply elements
9x+(4x+1)-3x-21=0
We get rid of parentheses
9x+4x-3x+1-21=0
We add all the numbers together, and all the variables
10x-20=0
We move all terms containing x to the left, all other terms to the right
10x=20
x=20/10
x=2
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