(4x+1)/(8x-4)=(2x+5)/(4x-15)

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Solution for (4x+1)/(8x-4)=(2x+5)/(4x-15) equation:


D( x )

8*x-4 = 0

4*x-15 = 0

8*x-4 = 0

8*x-4 = 0

8*x-4 = 0 // + 4

8*x = 4 // : 8

x = 4/8

x = 1/2

4*x-15 = 0

4*x-15 = 0

4*x-15 = 0 // + 15

4*x = 15 // : 4

x = 15/4

x in (-oo:1/2) U (1/2:15/4) U (15/4:+oo)

(4*x+1)/(8*x-4) = (2*x+5)/(4*x-15) // - (2*x+5)/(4*x-15)

(4*x+1)/(8*x-4)-((2*x+5)/(4*x-15)) = 0

(4*x+1)/(8*x-4)+(-1*(2*x+5))/(4*x-15) = 0

((4*x+1)*(4*x-15))/((8*x-4)*(4*x-15))+(-1*(2*x+5)*(8*x-4))/((8*x-4)*(4*x-15)) = 0

(4*x+1)*(4*x-15)-1*(2*x+5)*(8*x-4) = 0

5-88*x = 0

(5-88*x)/((8*x-4)*(4*x-15)) = 0

(5-88*x)/((8*x-4)*(4*x-15)) = 0 // * (8*x-4)*(4*x-15)

5-88*x = 0

5-88*x = 0 // - 5

-88*x = -5 // : -88

x = -5/(-88)

x = 5/88

x = 5/88

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