(4x+1)/3+(2x-1)/2-(3x-7)/5=6

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Solution for (4x+1)/3+(2x-1)/2-(3x-7)/5=6 equation: 



(4x+1)/3+(2x-1)/2-(3x-7)/5=6

We move all terms to the left:

(4x+1)/3+(2x-1)/2-(3x-7)/5-(6)=0

We calculate fractions

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