(4x+1)/3=(12x-3)/7

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Solution for (4x+1)/3=(12x-3)/7 equation: 


x in (-oo:+oo)

(4*x+1)/3 = (12*x-3)/7 // - (12*x-3)/7

(4*x+1)/3-((12*x-3)/7) = 0

(4*x+1)/3+(-1*(12*x-3))/7 = 0

(7*(4*x+1))/(3*7)+(-1*3*(12*x-3))/(3*7) = 0

7*(4*x+1)-1*3*(12*x-3) = 0

16-8*x = 0

(16-8*x)/(3*7) = 0

(16-8*x)/(3*7) = 0 // * 3*7

16-8*x = 0

16-8*x = 0 // - 16

-8*x = -16 // : -8

x = -16/(-8)

x = 2

x = 2

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