(4x+1)/4-(2x+3)/3=7/12

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Solution for (4x+1)/4-(2x+3)/3=7/12 equation: 


x in (-oo:+oo)

(4*x+1)/4-((2*x+3)/3) = 7/12 // - 7/12

(4*x+1)/4-((2*x+3)/3)-(7/12) = 0

(4*x+1)/4-((2*x+3)/3)-7/12 = 0

(4*x+1)/4+(-1*(2*x+3))/3-7/12 = 0

(3*12*(4*x+1))/(3*4*12)+(-1*4*12*(2*x+3))/(3*4*12)+(-7*3*4)/(3*4*12) = 0

3*12*(4*x+1)-1*4*12*(2*x+3)-7*3*4 = 0

48*x-108-84 = 0

48*x-192 = 0

(48*x-192)/(3*4*12) = 0

(48*x-192)/(3*4*12) = 0 // * 3*4*12

48*x-192 = 0

48*x-192 = 0 // + 192

48*x = 192 // : 48

x = 192/48

x = 4

x = 4

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