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(4x+1)/5+1=x
We move all terms to the left:
(4x+1)/5+1-(x)=0
We add all the numbers together, and all the variables
-1x+(4x+1)/5+1=0
We multiply all the terms by the denominator
-1x*5+(4x+1)+1*5=0
We add all the numbers together, and all the variables
-1x*5+(4x+1)+5=0
Wy multiply elements
-5x+(4x+1)+5=0
We get rid of parentheses
-5x+4x+1+5=0
We add all the numbers together, and all the variables
-1x+6=0
We move all terms containing x to the left, all other terms to the right
-x=-6
x=-6/-1
x=+6
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