(4x+1)/7=(x-2)

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Solution for (4x+1)/7=(x-2) equation: 



(4x+1)/7=(x-2)

We move all terms to the left:

(4x+1)/7-((x-2))=0

We multiply all the terms by the denominator


(4x+1)-(((x-2)))*7=0

We get rid of parentheses

4x-(((x-2)))*7+1=0

We move all terms containing x to the left, all other terms to the right

4x-(((x-2)))*7=-1

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