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(4x+1)/7=2/3x
We move all terms to the left:
(4x+1)/7-(2/3x)=0
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(4x+1)/7-(+2/3x)=0
We get rid of parentheses
(4x+1)/7-2/3x=0
We calculate fractions
There is no solution for this equation
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