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(4x+1)/7=2x/3.
We move all terms to the left:
(4x+1)/7-(2x/3.)=0
We add all the numbers together, and all the variables
(4x+1)/7-(+2x/3.)=0
We get rid of parentheses
(4x+1)/7-2x/3.=0
We calculate fractions
There is no solution for this equation
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