(4x+1)=(3x+29)

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Solution for (4x+1)=(3x+29) equation: 



(4x+1)=(3x+29)

We move all terms to the left:

(4x+1)-((3x+29))=0

We get rid of parentheses

4x-((3x+29))+1=0



We calculate terms in parentheses: -((3x+29)), so:

(3x+29)

We get rid of parentheses

3x+29

Back to the equation:

-(3x+29)



We get rid of parentheses

4x-3x-29+1=0

We add all the numbers together, and all the variables

x-28=0

We move all terms containing x to the left, all other terms to the right

x=28

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